Dice odds · 1% house edge
66% dice odds: 1.5x payout, streaks and bankroll
Every number on this page is calculated for a 66% win chance at a 1% house edge unless a table says otherwise. A win pays 1.5x, you lose 34% of rolls, and a run of 8 losses in a row starts about once every 8,483 rolls.
Payout and targets
- Payout multiplier
- 1.5x
- 99 ÷ 66
- Roll under
- < 66
- Bet low wins below this
- Roll over
- > 34.00
- Bet high wins above 100 − 66
- Win / loss chance
- 66% / 34%
- House edge
- 1%
- Return per 1 unit bet
- 0.9900
- Average loss 0.0100 per unit
The payout is (100 − house edge) ÷ win chance, so the same 66% chance pays a little more on a site with a lower edge. The table compares three edges. Return per unit is the win chance times the payout, which works out to 1 minus the edge at any chance.
| House edge | Payout | Return per 1 unit |
|---|---|---|
| 0% | 1.5152x | 1.0000 |
| 1% | 1.5x | 0.9900 |
| 2% | 1.4848x | 0.9800 |
Losing streaks
Each row gives the chance that the next N rolls all lose, the average number of rolls between such streaks, and the chance of seeing at least one within 10,000 and 100,000 rolls (1 − e−T/E, where E is the average gap). At 66%, 3 losses in a row is 1 in 25, while 15 in a row is 1 in 10,661,449.
| Streak | Chance next N all lose | Odds | Avg rolls between | At least one in 10,000 | At least one in 100,000 |
|---|---|---|---|---|---|
| 3 in a row | 3.93% | 1 in 25 | 37 | over 99.99% | over 99.99% |
| 4 in a row | 1.34% | 1 in 75 | 112 | over 99.99% | over 99.99% |
| 5 in a row | 0.454% | 1 in 220 | 332 | over 99.99% | over 99.99% |
| 6 in a row | 0.154% | 1 in 647 | 979 | over 99.99% | over 99.99% |
| 8 in a row | 0.018% | 1 in 5,600 | 8,483 | 69.24% | over 99.99% |
| 10 in a row | 2.1e-3% | 1 in 48,441 | 73,394 | 12.74% | 74.4% |
| 12 in a row | 2.4e-4% | 1 in 419,038 | 634,904 | 1.56% | 14.57% |
| 15 in a row | 9.4e-6% | 1 in 10,661,449 | 16,153,709 | 0.062% | 0.617% |
Exact counts over a fixed number of rolls are on the loss streak calculator.
Winning streaks
The same math with the 66% win chance. Positive progressions such as Paroli depend on these streaks, and the house edge is already inside the 1.5x payout each win pays.
| Streak | Chance next N all win | Odds | Avg rolls between | At least one in 10,000 | At least one in 100,000 |
|---|---|---|---|---|---|
| 5 in a row | 12.52% | 1 in 7.99 | 21 | over 99.99% | over 99.99% |
| 10 in a row | 1.57% | 1 in 64 | 185 | over 99.99% | over 99.99% |
| 15 in a row | 0.196% | 1 in 509 | 1,495 | 99.88% | over 99.99% |
| 20 in a row | 0.025% | 1 in 4,066 | 11,955 | 56.68% | 99.98% |
| 30 in a row | 3.9e-4% | 1 in 259,228 | 762,432 | 1.3% | 12.29% |
Martingale recovery
A recovery progression multiplies the bet after each loss so that one win pays back the run. At a 1.5x payout the smallest multiplier that does this is 3x, which is 1 + 1 ÷ (payout − 1). With it, a win after any number of losses ends the cycle 0.5 base bets ahead, the same as a win on the first roll.
The table shows the bankroll, in base bets, needed to place every bet of an N loss streak, for 3x and for 2x. The last column is where the cycle stands if the win comes right after those N losses at 2x. Because 2x is below the minimum, a win after 2 or more losses leaves the cycle behind.
| Losses survived | Bankroll at 3x | Bankroll at 2x | Cycle result at 2x |
|---|---|---|---|
| 3 | 13 | 7 | -3 |
| 4 | 40 | 15 | -7 |
| 5 | 121 | 31 | -15 |
| 6 | 364 | 63 | -31 |
| 8 | 3,280 | 255 | -127 |
| 10 | 29,524 | 1,023 | -511 |
What this chance is used for
66% pays 1.5x at a 1% house edge, so you win about two rolls in three while each win is worth half the stake.
Recovering a loss takes a big step: the minimum multiplier is 3x per loss, so even five losses in a row need a bankroll of more than a hundred base bets.
The house edge applies at every chance, so none of these settings has a positive expected return.
FAQ
What does a 66% win chance pay in dice?
At a 1% house edge a 66% chance pays 1.5x (99 divided by 66). You win when the roll is under 66, or over 34.00 if you bet high. A 1 unit bet returns 0.99 units on average, so the expected loss is 1% of every bet.
How often do you lose 8 times in a row at 66%?
Any given 8 rolls all lose with probability 0.018% (1 in 5,600). Such a streak starts on average once every 8,483 rolls, so the chance of seeing at least one is 69.24% within 10,000 rolls and over 99.99% within 100,000 rolls.
How much bankroll does martingale need at 66%?
To win back every loss at a 1.5x payout, the bet has to grow by at least 3x after each loss. Surviving 8 losses at that multiplier takes 3,280 base bets; at 2x it takes 255. The house edge still applies to every roll, so no multiplier makes the game profitable on average.