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Dice odds · 1% house edge

90% dice odds: 1.1x payout, streaks and bankroll

Every number on this page is calculated for a 90% win chance at a 1% house edge unless a table says otherwise. A win pays 1.1x, you lose 10% of rolls, and a run of 4 losses in a row starts about once every 11,110 rolls.

Payout and targets

Payout multiplier
1.1x
99 ÷ 90
Roll under
< 90
Bet low wins below this
Roll over
> 10.00
Bet high wins above 100 − 90
Win / loss chance
90% / 10%
House edge
1%
Return per 1 unit bet
0.9900
Average loss 0.0100 per unit

The payout is (100 − house edge) ÷ win chance, so the same 90% chance pays a little more on a site with a lower edge. The table compares three edges. Return per unit is the win chance times the payout, which works out to 1 minus the edge at any chance.

Payout and average return at 90% for three house edges
House edgePayoutReturn per 1 unit
0%1.1111x1.0000
1%1.1x0.9900
2%1.0889x0.9800

Losing streaks

Each row gives the chance that the next N rolls all lose, the average number of rolls between such streaks, and the chance of seeing at least one within 10,000 and 100,000 rolls (1 − e−T/E, where E is the average gap). At 90%, 2 losses in a row is 1 in 100, while 10 in a row is 1 in 10,000,000,000.

Losing streak odds at 90% win chance
StreakChance next N all loseOddsAvg rolls betweenAt least one in 10,000At least one in 100,000
2 in a row1%1 in 100110over 99.99%over 99.99%
3 in a row0.1%1 in 1,0001,11099.99%over 99.99%
4 in a row0.01%1 in 10,00011,11059.35%99.99%
5 in a row1.0e-3%1 in 100,000111,1108.61%59.34%
6 in a row1.0e-4%1 in 1,000,0001,111,1100.896%8.61%
7 in a row1.0e-5%1 in 10,000,00011,111,1100.09%0.896%
8 in a row1.0e-6%1 in 100,000,000111,111,1109.0e-3%0.09%
10 in a row1.0e-8%1 in 10,000,000,00011,111,111,1109.0e-5%9.0e-4%

Exact counts over a fixed number of rolls are on the loss streak calculator.

Winning streaks

The same math with the 90% win chance. Positive progressions such as Paroli depend on these streaks, and the house edge is already inside the 1.1x payout each win pays.

Winning streak odds at 90% win chance
StreakChance next N all winOddsAvg rolls betweenAt least one in 10,000At least one in 100,000
10 in a row34.87%1 in 2.8719over 99.99%over 99.99%
20 in a row12.16%1 in 8.2372over 99.99%over 99.99%
30 in a row4.24%1 in 24226over 99.99%over 99.99%
50 in a row0.515%1 in 1941,93099.44%over 99.99%
75 in a row0.037%1 in 2,70327,01830.94%97.53%

Martingale recovery

A recovery progression multiplies the bet after each loss so that one win pays back the run. At a 1.1x payout the smallest multiplier that does this is 11x, which is 1 + 1 ÷ (payout − 1). With it, a win after any number of losses ends the cycle 0.1 base bets ahead, the same as a win on the first roll.

The table shows the bankroll, in base bets, needed to place every bet of an N loss streak, for 11x and for 2x. The last column is where the cycle stands if the win comes right after those N losses at 2x. Because 2x is below the minimum, a win after 1 or more losses leaves the cycle behind.

Bankroll in base bets to survive N losses at 90%
Losses survivedBankroll at 11xBankroll at 2xCycle result at 2x
2123-2.6
31337-6.2
41,46415-13.4
516,10531-27.8
6177,15663-56.6
821,435,888255-229.4

What this chance is used for

90% pays 1.1x at a 1% house edge, so each win adds a tenth of the stake and a single loss takes back about ten wins.

Sessions at this chance look smooth for long stretches. To win back a loss in one roll the bet has to grow elevenfold, so two or three losses in a row are enough to put a progression far beyond most balances.

The house edge applies at every chance, so none of these settings has a positive expected return.

FAQ

What does a 90% win chance pay in dice?

At a 1% house edge a 90% chance pays 1.1x (99 divided by 90). You win when the roll is under 90, or over 10.00 if you bet high. A 1 unit bet returns 0.99 units on average, so the expected loss is 1% of every bet.

How often do you lose 4 times in a row at 90%?

Any given 4 rolls all lose with probability 0.01% (1 in 10,000). Such a streak starts on average once every 11,110 rolls, so the chance of seeing at least one is 59.35% within 10,000 rolls and 99.99% within 100,000 rolls.

How much bankroll does martingale need at 90%?

To win back every loss at a 1.1x payout, the bet has to grow by at least 11x after each loss. Surviving 4 losses at that multiplier takes 1,464 base bets; at 2x it takes 15. The house edge still applies to every roll, so no multiplier makes the game profitable on average.